2.00 mL of the unknown solution are mixed with 5.00 mL of a sodium standard containing 108 ppm Na

2.00 mL of the unknown solution are mixed with 5.00 mL of a sodium standard containing 108 ppm Na and diluted to 50.0 mL. Another 2.00 mL aliquot of the unknown is mixed with 10.00 mL of the same standard and also diluted to 50.0 mL. These give readings of 169 and 222, respectively.

(a) What is the concentration of sodium in the unknown solution?

Concentration of sodium (ppm):

(b) What is the sensitivity of the method?

Sensitivity of method (ppm-1)

Solution :-

(a) Let the conc. of sodium in unknown solution be 'x' ppm.

Therefore, take ratio of concentration in both solution

= 169 / 222

106 x = 62640

 x = 591 ppm of Na in unknown solution

(b) Sensitivity of method = Output range / Measurement range = OR/MR = 1/1000000

Sensivity of method = 10-6 ppm-1

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