The take-off speed of Airbus A340 is 288 Km/hr. From the taxi track it comes to the main runway and waits for a while for the final clearance from the Air Traffic Control. The aircraft then achieves this speed within 50 seconds. Neglecting the effect of the wind direction and friction, what should be the minimum length of main runway decided by civil engineers for this aircraft for a take-off?
Solution-
Given,
v= 288 Km/hr= 80 m/s
Therefore,
v=u+at
Therefore, 2000m should be the minimum length of main runway decided by civil engineers for this aircraft for a take-off.
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