A man of mass 80 Kg is standing on a trolley of mass 320 Kg resting on a smooth surface. If the man

A man of mass 80 Kg is standing on a trolley of mass 320 Kg resting on a smooth surface. If the man starts walking on the trolley at a speed of 1 m/s relative to trolley then displacement of man with respect to ground after 4 second is?

1. 3.2 m

2. 4 m

3. 4.8 m

4. 2 m

Solution

To Conserve the Momentum,

the trolley will move in the direction opposite to man's movement.

Therefore,

Now, let trolleys velocity be "v" and its mass be "m".

& let man's velocity be "V" and his mass be "M",

then,

we have,

Now, we have ,

m=320 Kg, M=80 Kg, V=1 m/s

by substituting these values in above equation, we get,

Distance covered by the man w.r.t. trolley is

Since, man has moved for 4 seconds, distance moved by trolley

As man has moved 4 m but trolley has moved 1 m in opposite direction. Hence, displacement of man with respect to ground is

Therefore, option (1) 3.2 m is correct answer.

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